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प्रश्न
A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹ 4000, then find the CP of the scooter.
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उत्तर
Let cost price of the scooter be ₹ x.
If he sells the scooter at a loss of 25%, then
SP = x – 25% of x
= `x - 25/100x`
= ₹ `75/100x`
And if he sells the scooter at a loss of 20%, then
SP = x – 20% of x
= `x - 20/100x`
= ₹ `80/100x`
It is given that the difference in the two SP’s is ₹ 4000.
∴ `80/100x - 75/100x = 4000`
⇒ `(80x - 75x)/100 = 4000`
⇒ `(5x)/100 = 4000`
⇒ `x = (4000 xx 100)/5` = ₹ 80000
Hence, cost price of scooter is ₹ 80000.
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Fill up the appropriate boxes in the following table
| SI. No | C.P. in ₹ |
S.P. in ₹ |
Profit in ₹ |
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| (i) | 100 | 120 | ||
| (ii) | 110 | 120 | ||
| (iii) | 120 | 20 | ||
| (iv) | 100 | 90 | ||
| (v) | 120 | 25 |
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