Question

A person wanted to sell a scooter at a loss of 25%. But at the last moment he changed his mind and sold the scooter at a loss of 20%. If the difference in the two SP’s is ₹ 4000, then find the CP of the scooter.

Answer 1

Let cost price of the scooter be ₹ x.

If he sells the scooter at a loss of 25%, then

SP = x – 25% of x

= `x - 25/100x`

= ₹ `75/100x`

And if he sells the scooter at a loss of 20%, then

SP = x – 20% of x

= `x - 20/100x`

= ₹ `80/100x`

It is given that the difference in the two SP’s is ₹ 4000.

∴ `80/100x - 75/100x = 4000`

⇒ `(80x - 75x)/100 = 4000`

⇒ `(5x)/100 = 4000`

⇒ `x = (4000 xx 100)/5` = ₹ 80000

Hence, cost price of scooter is ₹ 80000.