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प्रश्न
A person standing between two vertical cliffs produces a sound. Two successive echoes are heard at 4 s and 6 s. Calculate the distance between the cliffs. Take the speed of sound in air $$=320 \mathrm{~ms}^{-1}$$.
पर्याय
1000 m
1200 m
1400 m
1600 m
MCQ
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उत्तर
1600 m
Explanation:
Given: \[ t_1=4\,\text{s}\]
\[t_2=6\,\text{s}\]
\[v=320\,\text{m s}^{-1} \]
Distance from the first cliff:
\[ d_1=\frac{vt_1}{2}\]
\[=\frac{320\times4}{2}\]
\[= \frac{1280}{2}\]
= 640 m
Distance from the second cliff:
\[ d_2=\frac{vt_2}{2}\]
\[= \frac{320\times6}{2}\]
\[= \frac{1920}{2}\]
= 960 m
Distance between the cliffs:
\[ d = d_1+d_2\]
\[ =640+960\]
= 1600 m
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