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प्रश्न
A perfect square can never have the following digit in its ones place.
पर्याय
1
8
0
6
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उत्तर
8
Explanation:
We know that, a number ending with digits 2, 3, 7 or 8 can never be a perfect square.
Clearly, a perfect square can never have the digit 8 in its one’s place.
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संबंधित प्रश्न
Find the least number which must be added to the following numbers to make them a perfect square:
4931
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\[\frac{\sqrt{1587}}{\sqrt{1728}}\]
Evaluate: 372 – 362
Without doing the actual addition, find the sum of:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
Without doing the actual addition, find the sum of:
1 + 3 + 5 + 7 + 9 + ………………… + 51 + 53
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