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प्रश्न
A particle of mass ‘m’ is projected with a velocity υ = kVe (k < 1) from the surface of the earth.
(Ve = escape velocity)
The maximum height above the surface reached by the particle is:
पर्याय
`"Rk"^2/(1 - "k"^2)`
`"R"("k"/(1 - "k"))^2`
`"R"("k"/(1 + "k"))^2`
`("R"^2"k")/(1 + "k")`
MCQ
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उत्तर
`"Rk"^2/(1 - "k"^2)`
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