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प्रश्न
A particle of mass 5 × 10-5 kg is placed at the lowest point of a smooth parabola having the equation 20x2 = y (x, y in m). Here y is the vertical height. If it is displaced slightly and is constrained to move along the parabola, the angular frequency (in rad/s) of small oscillations is ______.
पर्याय
10.00
20.00
30.00
40.00
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उत्तर
A particle of mass 5 × 10-5 kg is placed at the lowest point of a smooth parabola having the equation 20x2 = y (x, y in m). Here y is the vertical height. If it is displaced slightly and is constrained to move along the parabola, the angular frequency (in rad/s) of small oscillations is 20.00.
Explanation:
The potential energy of particle = mgy
∴ `F_x = (-∂U)/(∂x)`
= `(-∂(20mgx^2))/(∂x)`
= -40 mgx
F ∝ -x, thus
`omega^2 = (40 xx 5 xx 10^-5 xx 10)/(5 xx 10^-5)`
⇒ ω = 20 rad s-1
