Question

A particle has its position moved from `vecr_1 =  3hati + 4hatj` to `vecr_2 =  hati + 2hatj`. Calculate the displacement vector `(∆vecr)` and draw the `vecr_1,  vecr_2` and `Deltavecr` vector in a two dimensional Cartesian coordinate system.

Answer 1

Given,

Position vectors `vecr_1 = 3hati + 4hatj`

`vecr_1 = hati + 2hatj`

Solution:

Displacement vector:

∆r = `vecr_2 - vecr_1 = (1 - 3)hati + (2 - 4)hatj`

∆r = `-2hati - 2hatj = -2(hati + hatj)`