Question

A metal piece of thermal capacity 40 JK⁻¹, absorbs 800 J of heat. Calculate the rise in the temperature of this metal piece.

Answer 1

Given: Thermal capacity of the metal piece = 40 JK⁻¹

Heat absorbed by the substance = 800 J

Let the rise in temperature be T.

The thermal capacity of a substance is given by,

Thermal capacity = `"Heat absorbed"/"Temperature rise"`

⇒ Temperature rise = `"Heat absorbed"/"Thermal capacity"`

= `800/40`

= 20 K

Since a rise of 1 K = 1°C, the rise in temperature is also 20°C.

∴ The rise in the temperature of the metal piece is 20°C.