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प्रश्न
A metal ball of mass 400 g and at 600°C is placed on a block of ice, when 428 g of ice melts. If the sp. heat capacity of the metal ball is 0.6 Jg−1°C−1, calculate sp. latent heat of ice.
संख्यात्मक
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उत्तर
As the block does not melt completely, therefore, final temperature is zero degree celsius.
| Substance | Mass | S.H.C./S.L.H. | Initial Temp. | Final Temp. = 0°C |
| Ice | 428 g | ?(L) | 0°C | ∴ θR = 0°С |
| Metal ball | 400 g | 0.6 Jg−1°C−1 | 600°C | ∴ θF = (600 − 0) = 600°С |
Heat gained by ice to melt = mLice
= 428 g × L
Heat lost by the metal ball = mcθF
= 400 × 0.6 × 600
= 144000 J
Heat gained = Heat lost
428 g × L = 144000 J
\[L=\frac{144000}{428} \mathrm{Jg}^{-1}\]
∴ L = 336.4 Jg−1
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