Advertisements
Advertisements
प्रश्न
A man can open a nut by applying a force of 150 N by using a lever handle of length 0.4 m. What should be the length of the handle if he is able to open it by applying a force of 60 N?
Advertisements
उत्तर
Given,
F1 = 150N
l1 = 0.4m
F2 = 60N
l2 = ?
∵ Force × perpendicular distance = constant
F1 × l1 = F2 × l2
150 × 0.4 = 60 × l2
l2 = 1m
APPEARS IN
संबंधित प्रश्न
Define the term Force?
Give one example in the given cases:-
A force moves a stationary body
Give one example in the given cases:-
A force changes the shape of a body
Explain what is understood by the following statement 1 kilogram-force (kgf) - 9.8 newton
How can you feel a force of 1 N?
Complete the following
Newton is the unit of .................
A body of mass 50g is moving with the velocity of 10 ms-1. It is brought to rest by a resistive force of 10 N Find.
1) the retardation and
2) the distance that the body will travel after the resistive force is applied.
A force od 10 kgf is applied on a body of mass 100 g initially at rest for 0.1 s calculate:
a) the momentum acquired by the body
b) the distance travelled by the body in 0.1s. Take g = 10 N kg-1
In which of the following sport the turning of the effect of force used
In ‘tug of war’ when two teams pull equally hard, then what happens?
