मराठी

A longitudinal wave is represented by x = 10 sin 2π nt(nt-xλ) cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to ______.

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प्रश्न

A longitudinal wave is represented by x = 10 sin 2π `("nt" - x/lambda)` cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to ______.

पर्याय

  •  2π

  • π

  • `(5pi)/2`

MCQ
बेरीज
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उत्तर

A longitudinal wave is represented by x = 10 sin 2π `("nt" - x/lambda)` cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to .

Explanation:

y = 10 sin 2π `("nt" - x/lambda)`

y = 10 sin `(2pi"nt" - (2pi)/lambdax)`

On comparing it with standard equation of wave

⇒ ω 2pn and k = `(2pi)/lambda`

Given : Maximum particle velocity = 4 × wave velocity

In wave propagation, medium particle oscillates and maximum velocity of oscillating particle is equal to Aω 

Where, A ⇒ Amplitude

ω ⇒ Angular frequency

⇒ Wave velocity is given by V = `ω/"k"` where, k is angular wave number and k = `(2pi)/lambda`

Vwave = `(2pin)/(2pilambda)` = nλ

`"V"_("particle")` = 4 Vwave 

Aω = 4nλ

A × 2πn = 4nλ

A × 2 πn = 4nλ

λ = `(2pi"A")/4 = (pi"A")/2`

As,  A = 10

⇒ λ = `(pixx10)/2` 

= 5π 

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