Advertisements
Advertisements
प्रश्न
A longitudinal wave is represented by x = 10 sin 2π `("nt" - x/lambda)` cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to ______.
पर्याय
2π
5π
π
`(5pi)/2`
Advertisements
उत्तर
A longitudinal wave is represented by x = 10 sin 2π `("nt" - x/lambda)` cm. The maximum particle velocity will be four times the wave velocity if the determined value of wavelength is equal to 5π.
Explanation:
y = 10 sin 2π `("nt" - x/lambda)`
y = 10 sin `(2pi"nt" - (2pi)/lambdax)`
On comparing it with standard equation of wave
⇒ ω 2pn and k = `(2pi)/lambda`
Given : Maximum particle velocity = 4 × wave velocity
In wave propagation, medium particle oscillates and maximum velocity of oscillating particle is equal to Aω
Where, A ⇒ Amplitude
ω ⇒ Angular frequency
⇒ Wave velocity is given by V = `ω/"k"` where, k is angular wave number and k = `(2pi)/lambda`
Vwave = `(2pin)/(2pilambda)` = nλ
`"V"_("particle")` = 4 Vwave
Aω = 4nλ
A × 2πn = 4nλ
A × 2 πn = 4nλ
λ = `(2pi"A")/4 = (pi"A")/2`
As, A = 10
⇒ λ = `(pixx10)/2`
= 5π
