Question

A liquid of mass 0.2 kg and at a temperature 135°C is cooled to 25°C. If specific heat capacity of liquid is 750 J kg⁻¹°C⁻1, the heat energy given out by liquid is:

पर्याय

• 15600 J

• 16500 J

• 16600 J

• 5160 J

Answer 1

16500 J

Explanation:

Fall in temperature θ_F = (135− 25) = 110°C

∴ Heat = mcθ_F

= 0.2 kg × 750 J kg⁻¹°C⁻¹ × 110°C

= 16500 J