Question

A line segment of length 10 units has one end at A (-4 , 3). If the ordinate of te othyer end B is 9 , find the abscissa of this end.

Answer 1

A (-4 , 3) ,Let the other point B (x , 9)

Given , AB = 10 units

`sqrt ((-4-"x")^2 + (3 - 9)^2)` = 10

squaring both sides ,

⇒ 16 + x² + 8x + 36 = 100

⇒ x² + 8x - 48 = 0

⇒ x² + 12x - 4x - 48 = 0

⇒ x (x + 12) - 4(x + 12) = 0

⇒ (x - 4) (x + 12) = 0

⇒  x = 4 or -12

The abscissa of other end is 4 or -12.