Question

A letter of English alphabet is chosen at random from English alphabets.

Assertion (A): The probability that the chosen letter is not a consonant is (5 : 26).

Reason (R): The probability of an event \[=\frac{\text {Total number of outcomes }}{\text { Number of favourable outcomes }}\]

पर्याय

• A is true, R is false.

• A is false, R is true.

• Both A and R are true and R is the correct reason for A.

• Both A and R are true and R is the incorrect reason for A.

Answer 1

A is true, R is false.

Explanation:

Given, there are 26 letters in the English alphabet.

There are total 5 (a, e, i, o, u) vowels and the remaining 21 letters are consonants.

A letter that is 'not a consonant' is a vowel.

∴ Probability that the chosen letter is not a consonant = \[\frac{\text{Number of vowels}}{\text{Total number of letters}} = \frac{5}{26}.\] i.e. 5 : 26.

So, assertion (A) is true.

By formula,

The probability of an event = \[\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}\]

The relation given in reason (R) is inverted.

So, reason (R) is false.

∴ A is true and R is false.