Question

A ladder is placed along a wall of a house such that its upper end is touching the top of the wall. The foot of the ladder is 2 m away from the wall and the ladder is making an angle of 60° with the level of the ground. Determine the height of the wall.

Answer 1

Let AB be the wall of height, hm and C be the points, makes an angle 60° and foot of the ladder is 2m away from the wall. We have to find the height of the wall

In a triangle ABC, given that BC = 2m and angle C = 60°

Now we have to find the height of the wall.

So we use trigonometrically ratios.

In a triangle ABC

`=> tan C = (AB)/(BC)`

`=> tan 60^@ = h/2`

`=> sqrt3 = h/2`

`=> h = 2sqrt3`

Hence height of wall is `2sqrt3` meters