Question

A ladder 10 m long reaches the window of a house 8 m above the ground. Find the distance of the foot of the ladder from the base of the wall. 

Answer 1

   

Let AB be A ladder and B is the window at 8 m above the ground C.
Now, In right triangle ABC
By using Pythagoras theorem, we have 

`AB^2=BC^2+CA^2` 

⇒ `10^2=8^2+CA^2` 

⇒ `CA^2=100-64` 

⇒ `CA^2=36` 

⇒` CA=6m` 

Hence, the distance of the foot of the ladder from the base of the wall is 6 m.