Question

A KCl solution of conductivity 0.14 S m⁻¹ shows a resistance of 4.19 Ω in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03 Ω. The conductivity of the HCl solution is ______ × 10⁻² S m⁻¹

(Round off to the nearest integer)

Answer 1

A KCl solution of conductivity 0.14 S m⁻¹ shows a resistance of 4.19 Ω in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03 Ω. The conductivity of the HCl solution is 57 × 10⁻² Sm⁻¹

Explanation:

Given: Conductivity of KCl solution, κ_KCl = 0.14 S m⁻¹

Resistance of KCl solution, R_KCl = 4.19 Ω

Resistance of HCl solution, R_HCl = 1.03 Ω

Formula: `kappa = 1/R` × cell constant

Cell constant = κ_KCl ​× R_KCl​

= 0.14 × 4.19

= 0.5866 m⁻¹

Conductivity of HCl solution (κ_HCl) = `"Cell constant"/R_"HCl"`

= `0.5866/1.03`

= 0.5695 S m⁻¹

= 56.95 × 10⁻² S m⁻¹

= 57 × 10⁻² S m⁻¹