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प्रश्न
A hyperbola passes through (2, 3) and has asymptotes \[3x-4y+5=0\] and \[12x+5y-40=0,\] then the equation of its transverse axis is______.
पर्याय
\[77x-21y-265=0\]
\[21x-77y+265=0\]
\[21x-77y-265=0\]
\[21x+77y-265=0\]
MCQ
रिकाम्या जागा भरा
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उत्तर
A hyperbola passes through (2, 3) and has asymptotes \[3x-4y+5=0\] and \[12x+5y-40=0,\] then the equation of its transverse axis is \[21x+77y-265=0\].
Explanation:
Transverse axis is the equation of the angle bisector containing point (2, 3)0 which is given by
\[\frac{3x-4y+5}{5}=\frac{12x+5y-40}{13}\]
\[\Rightarrow\quad13(3x-4y+5)=5(12x+5y-40)\]
\[\Rightarrow\quad21x+77y=265\]
shaalaa.com
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