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प्रश्न
A hydrocarbon of mass 1.5 kg is just kept in the molten state by a heater of 500 W. If the heater is switched off, the temperature starts dropping after 4 min. Calculate sp. latent heat of fusion of the hydrocarbon.
संख्यात्मक
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उत्तर
The heat supplied while the hydrocarbon changes state is Q = Pt.
Time = 4 × 60 = 240 s
Q = 500 × 240 = 120000 J
Using Q = mL
$$L = \frac{Q}{m}$$
$$= \frac{120000}{1.5}$$
= 80000 Jkg−1
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