Question

A hemispherical bowl is made of steel of thickness 1 cm. The outer radius of the bowl is 6 cm. The volume of steel used (in cm³) is ______.

पर्याय

• 182 π

• `182/3 π`

• `682/3 π`

• `364/3 π`

Answer 1

A hemispherical bowl is made of steel of thickness 1 cm. The outer radius of the bowl is 6 cm. The volume of steel used (in cm³) is `underlinebb(182/3 π)`.

Explanation:

Given:

Outer Radius (R) = 6 cm

Thickness = 1 cm

Inner Radius (r) = Outer radius – Thickness

r = 6 – 1

= 5 cm

Volume of steel = Outer volume – Inner volume

Volume = `2/3 πR^3 - 2/3 πr^3`

= `2/3 π (R^3 - r^3)`

= `2/3 π (6^3 - 5^3)`

= `2/3 π (216 - 125)`

= `2/3 π (91)`

= `182/3 π cm^3`