मराठी

A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 windows 1 m by 80 cm. Find the i. area of the 4 walls (excluding the door and windows). - Mathematics

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प्रश्न

A hall is 10 m long, 5 m wide and 4 m high. It has one door 2 m by 1 m and 2 windows 1 m by 80 cm. Find the

  1. area of the 4 walls (excluding the door and windows).
  2. cost of distempering the walls at ₹ 50 per m2.
  3. cost of polishing the floor at the rate of ₹ 5 per m2.
बेरीज
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उत्तर

Given:

  • Hall dimensions: length = 10 m, width = 5 m, height = 4 m
  • Door dimensions: 2 m by 1 m
  • Window dimensions: 1 m by 80 cm (0.8 m) and there are 2 such windows
  • Cost of distempering = ₹ 50 per m2
  • Cost of polishing floor = ₹ 5 per m2

i. Area of the 4 walls (excluding the door and windows)

Step 1: Calculate total area of 4 walls

Walls consist of two lengths and two widths:

Area of 4 walls = 2 × height × (length + width)

= 2 × 4 × (10 + 5)

= 2 × 4 × 15

= 120 m2

Step 2: Calculate area of door and windows

Door area = 2 × 1 = 2 m2

Window area for one window = 1 × 0.8 = 0.8 m2

For 2 windows = 2 × 0.8 = 1.6 m2

Total door and window area = 2 + 1.6 = 3.6 m2

Step 3: Calculate wall area excluding door and windows

Excluding area = 120 − 3.6 = 116.4 m2

ii. Cost of distempering the walls at ₹ 50 per m2

Cost = Area to be distempered × Rate per m2

= 116.4 × 50

= ₹ 5820

iii. Cost of polishing the floor at the rate of ₹ 5 per m2

Floor area = length × width

= 10 × 5

= 50 m2

Cost = Floor area × Rate per m2

= 50 × 5

= ₹ 250

Area of 4 walls (excluding door and windows) = 116.4 m2

Cost of distempering walls = ₹ 5820

Cost of polishing floor = ₹ 250

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पाठ 18: Surface Area and Volume of Solids - EXERCISE 18 [पृष्ठ २२४]

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बी निर्मला शास्त्री Mathematics [English] Class 9 ICSE
पाठ 18 Surface Area and Volume of Solids
EXERCISE 18 | Q 24. | पृष्ठ २२४
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