Question

A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 and these are equally likely outcomes. Find the probability that the arrow will point at any factor of 8.

Answer 1

Total number of outcomes = 8

Let E be the event that the arrow will point at any factor of 8. So, the outcomes in favour of the event E are 1, 2, 4 and 8.

Total number of favourable outcomes = 4

\[\therefore P\left( E \right) = \frac{\text{Total number of favourable outcomes}}{\text{Total number of outcomes}} = \frac{4}{8} = \frac{1}{2}\]

Thus, the probability that the arrow will point at any factor of 8 is

\[\frac{1}{2}\]