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प्रश्न
A galvanometer of resistance 30 `Omega` is connected to a battery of emf 2V with 1970 `Omega` resistance in series. A full scale deflection of 20 divisions is obtained in the galvanometer. To reduce the deflection to 10 divisions, the resistance in series required is ____________.
पर्याय
4030 `Omega`
4000 `Omega`
3970 `Omega`
2000 `Omega`
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उत्तर
A galvanometer of resistance 30 `Omega` is connected to a battery of emf 2V with 1970 `Omega` resistance in series. A full scale deflection of 20 divisions is obtained in the galvanometer. To reduce the deflection to 10 divisions, the resistance in series required is 3970 `Omega`.
Explanation:

`"I" = "V"/(("R" + "r"))`
` = 2/((1970 + 30))`
` = 2/2000`
` = 1 "mA"`
∴ for 10 divisions of deflection,
I = 0.5 mA
`therefore 0.5 xx 10^-3 = 2/(("R" + "r"))`
`therefore "R'" + "r" = 2/(0.5 xx 10^-3)`
`therefore "R'" = (4 xx 10^3) - 30`
`therefore "R'" = 3970 Omega`
