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प्रश्न
A force of 40 N is required to pull up cylindrical barrel of mass 2.5 kg through a distance of 7.5 m along the inclined plane as shown in diagram alongside. Calculate.
- Force of gravity acting on the barrel. (Take g = 10 ms−2)
- Work done by the force in pulling body along the inclined plane.
- Work done against the force of gravity.
संख्यात्मक
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उत्तर
(a) Force of gravity (weight) = mg
= 2.5 × 10
= 25 N
(b) Work done by the pulling force = force × distance
= 40 × 7.5
= 300 J
(c) The vertical height of the incline is h = 7.5 sin 30° = 3.75 m.
Therefore, work done against gravity = mgh
= 2.5 × 10 × 3.75
= 93.75 J
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