Advertisements
Advertisements
प्रश्न
A fixed pulley is driven by a 100 kg mass falling at a rate of 8.0 m in 4.0 s. It lifts a load of 75.0 kgf. Calculate the efficiency of the pulley.
संख्यात्मक
Advertisements
उत्तर
Load pulled by the pulley is L = 75 × 10 = 750 N
Therefore, M.A. is
M.A. = `"L"/"E" = 750/1000 = 0.75`
When the effort moves by a distance d downwards, the load moves by the same distance upwards. So, V.R. = 1
Hence, efficiency is
η = `"M.A."/"V.R." = 0.75/1` = 0.75 (or 75 %)
shaalaa.com
Machines (Numerical)
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
