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प्रश्न
A firm has the revenue function R = 600q - 0.03q2 and the cost function is C = 150q + 60,000, where q is the number of units produced. Find AR, AC, MR, and MC.
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उत्तर
Given:
R = 600q – 0.03q2
C = 150q + 60000
- AR = \(\frac { R }{ q }\)
= \(\frac{600 q-0.03 q^{2}}{q}\)
= \(\frac { 600q }{ q }\) – \(\frac{0.03 \mathrm{q}^{2}}{\mathrm{q}}\)
= AR = 600 – 0.0.q - AC = \(\frac { c }{ q }\)
= \(\frac { 150q + 60000 }{ q }\)
= \(\frac { 150q }{ q }\) + \(\frac { 60000 }{ q }\)
AC = 150 + (\(\frac { 60000 }{ q }\)) - MR = \(\frac { dr }{ dq }\)
R = 600q – 0.03q
\(\frac { dR }{ dq }\) = 600 (1) – 0.03 (2q)
MR = 600 – 0.06q - MC = \(\frac { dc }{ dq }\)
C = 150q + 60000
\(\frac { dc }{ dq }\) = 150 (1) + 0
MC = 150
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