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A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m0 of a particle in terms of its speed v and the speed of light, c. (This relation first aro - Physics

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प्रश्न

A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m0 of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes:

`m = m_0/(1-v^2)^(1/2)`

Guess where to put the missing c.

संख्यात्मक
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उत्तर

From the given equation, `m_0/m = sqrt(1-v^2)`

Left hand side is dimensionless

Therefore, right hand side should also be dimensionless.

It is possible only when `sqrt(1-v^2)  "should be" sqrt(1-v^2/c^2)`

Thus the correct formula is m = `m_0 (1 - v^2/c^2)^((-1)/2)`

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पाठ 1: Units and Measurements - Exercise [पृष्ठ ११]

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एनसीईआरटी Physics [English] Class 11
पाठ 1 Units and Measurements
Exercise | Q 1.13 | पृष्ठ ११
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