Question

A die is thrown once. Find the probability of getting a number which (i) is a prime number (ii) lies between 2 and 6.

Answer 1

Total possible outcomes that occur after throwing a die once are 1,2,3,4,5,6

Number of possible outcomes = 6

(a) We need to find the probability of  getting a prime number
Prime number is a number not divisible by any number except itself
Prime numbers on dice are 2,3 and 5.
Number of favourable outcomes =3

Probability of getting a prime number = `"Number of favourable outcomes"/"Total number of possible outcomes"`

Probability of getting a prime number=`3/6 = 1/2`

Therefore, probability of getting a prime number is `1/2`

(b) Probability of getting a number lying between 2 and 6

Number lying between 2 and 6 on a dice are 3,4 and 5.

Probability of getting a number lying between 2 and 6 =`3/6 = 1/2`

Therefore, Probability of getting a number lying between 2 and 6 is = `1/2`