Question

A die is thrown 300 times and outcomes are noted as given below :

Outcomes	1	2	3	4	5	6
Frequency	50	73	55	44	45	33

When the same die is thrown once more, what is the probability of getting :

1. 4?
2. 6?
3. 5?
4. 2?

Answer 1

Total number of trials = 50 + 73 + 55 + 44 + 45 + 33 = 300.

By formula,

Probability of an event = \[\frac{\text{Number of favourable outcomes}}{\text{Total number of trials}}\]

i. Number of times 4 appears = 44

∴ P(getting 4) = \[\frac{44}{300} = \frac{11}{75}\]

Hence, P(getting 4) = \[\frac{11}{75}\]

ii. Number of times 6 appears = 33

∴ P(getting 6) = \[\frac{33}{300} = \frac{11}{100}\]

Hence, P(getting 6) = \[\frac{11}{100}\]

iii. Number of times 5 appears = 45

∴ P(getting 5) = \[\frac{45}{300} = \frac{3}{20}\]

Hence, P(getting 5) = \[\frac{3}{20}\]

iv. Number of times 2 appears = 73

∴ P(getting 2) = \[\frac{73}{300}\]

Hence, P(getting 2) = \[\frac{73}{300}\]