Question

A cylindrical glass with diameter 20 cm has water to a height of 9 cm. A small cylindrical metal of radius 5 cm and height 4 cm is immersed it completely. Calculate the raise of the water in the glass?

Answer 1

Radius of the cylindrical glass (r) = 10 cm

Height of the water (h) = 9 cm

Radius of the cylindrical metal (R) = 5 cm

Height of the metal (H) = 4 cm

Let the height of the water raised be h

Volume of the water raised in the cylinder = Volume of the cylindrical metal

πr²h = πr²H

π × 10² × h = π × 5² × 4

h = `100/100`

h = 1 cm

∴ The height of the raised water in the glass = 1 cm.