Question

A cylindrical container of volume 4.0 × 10^-3 m³ contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is ______.

[Take gas constant as 8.3 J mol^-1 K^-1]

पर्याय

• 249 × 10¹ Pa

• 24.9 × 10³ Pa

• 24.9 × 10⁵ Pa

• 24.9 Pa

Answer 1

A cylindrical container of volume 4.0 × 10^-3 m³ contains one mole of hydrogen and two moles of carbon dioxide. Assume the temperature of the mixture is 400 K. The pressure of the mixture of gases is 24.9 × 10⁵ Pa.

Explanation:

Given,

Volume of cylinder, V = 4 × 10^-3 m³

n = 1 + 2 = 3 moles

The temperature of the mixture, T = 400K

From the ideal gas equation,

⇒ PV = nRT ⇒ P = `(nRT)/V`

⇒ P = `(3 xx 8.3 xx 400)/(4 xx 10^-3)` ⇒ P = 24.9 × 10⁵ Pa