Question

A cylinderical container with a diameter of base 42 cm contains sufficient water to submerge a rectangular solid of iron with dimesions 22 cm × 14 cm × 10.5 cm. Find the rise in level of the water when the solid is submerged.

Answer 1

Given:

cylindrical container

D = 42 cm

r = `42/2 = 21` cm

H = ?

Rectangular solid

l = 22

b = 14

h = 10.5 cm

The volume of container = The volume of solid

πr²H = l × b × h

`22/7 xx 21 xx 21 xx "H" = 22 xx 14 xx 10.5`

`"H" = (22 xx 14 xx 10.5 xx 7)/(22 xx 21 xx 21)`

= `(2 xx 10.5)/9`

= `21/9`

= `7/3`

H = `2 1/3`  or 2.33 cm