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प्रश्न
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. The relative molecular mass of this compound is 168, so what is its molecular formula?
संख्यात्मक
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उत्तर
Empirical formula mass = 12 × 1 + 1 × 1 + 35.5 × 2
= 12 + 1 + 71
= 84
Relative molecular mass (given) = 168
n = `"Relative molecular mass"/"Empirical formula mass"`
= `168/84`
n = 2
Molecular formula = (CHCl2)2
= C2H2Cl4
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या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole Concept And Stoichiometry - Exercise 8 [पृष्ठ १२२]
