Question

A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given, π = 3.14) is

पर्याय

• 32.5 cm²

•  34.5 cm²

• 28.5 cm²

• 30.5 cm²

Answer 1

Area of minor segment = Area of sector AOBC - Area of right traingle AOB

`= 90^circ/360^circpi("OA")^2-1/2xx"OA"xx"OB"`

`=1/4xx3.14xx(10)^2-1/2xx10xx10`

= 78.5 - 50

= 28.5 cm²

Hence, the correct answer is option (c).