Question

A charge \[q_0\] is moved from point A to point B on the same equipotential surface. If the potentials at A and B are \[V_A\] and \[V_B\] respectively, the work done is:

पर्याय

• \[W = q_0(V_A - V_B) \neq 0\]

• \[W = q_0(V_A + V_B)\]

• \[W = \frac{q_0}{(V_A - V_B)}\]

• \[W = q_0(V_A - V_B) = 0\]

Answer 1

The work done in moving a charge \[q_0\] from A to B is \[W = q_0(V_A - V_B)\]. Since both points lie on the same equipotential surface, \[V_A = V_B\], which forces the work done to be exactly zero regardless of the path taken along the surface.