Question

A charge of 9600 C flows through an electric circuit in 2 min and 40 s. The magnitude of current flowing through the electric circuit is:

पर्याय

• 0.60 A

• 6.0 A

• 60.0 A

• 40.0 A

Answer 1

60.0 A

Explanation:

Time = 2 min 40 s

= 2 × 60 + 40

= 160 s

$$I = \frac{Q}{t}$$

$$= \frac{9600}{160}$$

= 60 A