Question

A charge of \[1.6\times10^{-11}\,\mathrm{C}\] produces a potential difference of \[10\,\mathrm{V}\]. What capacitance follows from \[C=\frac{Q}{V}\]?

पर्याय

• \[1.6\times10^{-9}\,\mathrm{F}\]

• \[1.6\times10^{-10}\,\mathrm{F}\]

• \[1.6\times10^{-11}\,\mathrm{F}\]

• \[1.6\times10^{-12}\,\mathrm{F}\]

Answer 1

Capacitance is charge divided by potential difference. Substituting gives \[C=\frac{1.6\times10^{-11}}{10}=1.6\times10^{-12}\,\mathrm{F}\], or \[1.6\,\mathrm{pF}\].