Advertisements
Advertisements
प्रश्न
A boy explodes a cracker in front of a high-rise building 132.8 m away and hears an echo after 0.8 s. The speed of sound in air is:
पर्याय
336 ms−1
332 ms−1
331 ms−1
330 ms−1
MCQ
Advertisements
उत्तर
332 ms−1
Explanation:
Total distance = 2 × d
= 2 × 132.8
= 265.6 m
v = `(2d)/t`
= `265.6/0.8`
= 332 ms−1
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
