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प्रश्न
A body performing linear S.H.M. experiences a force of 0.2 N when displaced through 4 cm from the mean position. Its force constant will be ______.
पर्याय
2 N/m
2.5 N/m
5 N/m
8 N/m
MCQ
रिकाम्या जागा भरा
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उत्तर
A body performing linear S.H.M. experiences a force of 0.2 N when displaced through 4 cm from the mean position. Its force constant will be 5 N/m.
Explanation:
K = `F/x`
Putting F = 0.2 N and x = 4 cm = 4 × 10−2 m
∴ K = `0.2/(4 xx 10^-2)`
= `(0.2 xx 10^2)/4`
= `20/4`
= 5 N/m
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