Advertisements
Advertisements
प्रश्न
A body of mass m falls from a height h1 to a height h2, above the ground (h1 > h2). What is the loss of potential energy?
Advertisements
उत्तर
At height h1, initial potential energy of body = mgh1
At height h2, final potential energy of body = mgh2
Loss in potential energy = Initial potential energy − Final potential energy
= (mgh1 − mgh2)
= mg (h1 − h2)
संबंधित प्रश्न
Give one example of a body that has potential energy, due to its position at a height.
Name the physical quantity measured in terms of horse power.
State the work energy theorem.
State the energy changes in the following case while in use:
an electric cell in a circuit
State two disadvantages of using nuclear energy for producing electricity.
Show that the quantity 2K/v2 has the unit of mass, where K is the kinetic energy of the body.
A pebble is thrown up. It goes to a height and then comes back on the ground. State the different changes in form of energy during its motion.
A body of mass 5 kg falls from a height of 10 m to 4 m. Calculate:
The total energy possessed by the body at any instant? (Take g = 10 ms-2).
State the energy changes which take place when:
During electrolysis.
A body of mass 50 kg has a momentum of 3000 kg−1 ms. Calculate:
(j) the kinetic energy of the body.
(ii) the velocity of the body.
