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प्रश्न
A body of mass 5 kg is moving with a velocity of 10 ms−1. What will be the ratio of its initial kinetic energy and final kinetic energy, if the mass of the body is doubled and its velocity is halved?
संख्यात्मक
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उत्तर
For a body of mass 5 kg:
Initial kinetic energy:
`K_i = 1/2mv_i^2`
= `1/2 xx 5 xx 10^2`
= 250 J
If the final velocity is v, then
`K_f = 1/2 xx 5 xx v^2`
Therefore,
`K_i : K_f = 10^2 : v^2`
`K_i : K_f = 100 : v^2`
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