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प्रश्न
A body has a KE 'P'. If the mass of body increases 25 times, calculate its velocity, the kinetic energy remaining same.
संख्यात्मक
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उत्तर
Let initial velocity = v
\[ \therefore \text{KE} = \frac{1}{2}mv^{2} \qquad \text{.....(i)} \]
When mass increases 25 times, let velocity be v1,
\[ \therefore \text{KE} = \frac{1}{2} \times 25\ mv_{1}^{2} \qquad \text{.....(ii)} \]
As KE remains the same,
\[ \therefore\ \frac{1}{2} \times 25\, m v_{1}^{2} = \frac{1}{2}\, m v^{2} \]
\[ 25\, v_{1}^{2} = v^{2} \]
Or \[v_{1} = \frac{v}{5}\]
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