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प्रश्न
A black body radiates maximum energy at wavelength ‘λ’ and its emissive power is ‘E’. Now due to change in temperature of that body, it radiates maximum energy at wavelength `(3λ)/4`. At that temperature emissive power is ______.
पर्याय
`81/16`
`81/256`
`16/81`
`256/81`
MCQ
रिकाम्या जागा भरा
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उत्तर
A black body radiates maximum energy at wavelength ‘λ’ and its emissive power is ‘E’. Now due to change in temperature of that body, it radiates maximum energy at wavelength `(3λ)/4`. At that temperature emissive power is `bbunderline(256/81)`.
Explanation:
Emissive power of a black body is,
E = σT4
According to Wien’s displacement law,
`λ = b/T`
∴ E = `(σb^4)/(λ^4)`
∴ `E_2/E_1 = λ_1^4/λ_2^4`
∴ `E_2/E_1 = λ^4/((3λ)/4)^4`
= `λ^4/((81λ^4)/256)`
= `λ^4 xx 256/(81λ^4)`
= `256/81`
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