Question

A balloon filled with an air sample occupies a 3 L volume at 35°C. On lowering the temperature to T, the volume decreases to 2.5 L. The temperature T is?

[Assume p-constant]

पर्याय

• 16°C

• −16°C

• 24°C

• −20°C

Answer 1

−16°C

Explanation:

V₁ = 3 L

T₁ = 273 + 35 = 308 K

V₂ = 2.5 L

T₂ = ?

According to Charle’s law

`V_1/T_1 = V_2/T_2`

`3/308 = 2.5/T_2`

`T_2 = (2.5 xx 308)/3`

`T_2 = 770/3`

T₂ = 256.6 K

T(K) = t(°C) + 273

t(°C) = T(K) − 273

t = 256.6 − 273

= −16.4°C

≈ −16°C