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प्रश्न
A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is not black.
बेरीज
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उत्तर
Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black}
E ⟶ event of getting no black ball
No. of favourable outcomes = 4 {4 black balls}
Probability, P(E) =`"No. of favorable outcomes"/"Total no. of possible outcomes"`
P(E) = `4/18`
= `2/9`
`(barE)` ⟶ event of not getting black ball
`P(barE) = 1 - P(E)`
= `1 - 2/9`
= `7/9`
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