Question

A 60 g bullet fired from a 5 kg gun leaves with a speed of 500 m/s. Find the speed (velocity) with which the gun recoils (jerks backwards).

Answer 1

Here , mass of bullet = 60 g
= `60/1000`
= 0.06 kg
velocity of bullet = 500 m/s
mass of gun = 5 kg
Now, putting these values in the formula:
Mass of bullet × Velocity of bullet = Mass of gun × Recoil velocity of gun
We get,
0.06 × 500 – 5 × Recoil velocity of gun
Recoil velocity of gun = `(0.06 xx 500)/5`
= `(0.06 xx 500)/5`
= `(0.06 xx 500)/5`
= 0.06 xx 100
Recoil velocity of gun = 6 m/s