Advertisements
Advertisements
प्रश्न
A `117 1/3` m long rope is cut into equal pieces measuring `7 1/3` m each. How many such small pieces are these?
Advertisements
उत्तर
We have,
Length of rope
= `117 1/3` m
= `(117 xx 3 + 1)/3` m
= `352/3` m
Length of each piece
= `7 1/3` m
= `22/3` m
So, the number of pieces of the rope
= `"Total length of the rope"/"Length of each piece"`
= `(352/3)/(22/3)`
= `352/3 ÷ 22/3`
= `352/3 xx 3/22`
= 16
Hence, number of small pieces cut from the `117 1/3` m long rope is 16.
APPEARS IN
संबंधित प्रश्न
Find the multiplicative inverse `(-5)/8 xx (-3)/7`
The numbers ______ and ______ are their own reciprocal.
Fill in the blanks
The reciprocal of a positive rational number is ________.
The reciprocal of 0 is ______.
If y be the reciprocal of x, then the reciprocal of y2 in terms of x will be ______.
If a ≠ 0, the multiplicative inverse of `a/b` is `b/a`.
Simplify
`3/7 xx 28/15 ÷ 14/5`
Simplify
`7/8 + 1/16 - 1/12`
Find the multiplicative inverse of `3 1/3`
From a rope 40 metres long, pieces of equal size are cut. If the length of one piece is `10/3` metre, find the number of such pieces.
