Question

A 10 µF capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly ______.

(π = 3.14)

पर्याय

• 1.20 A

• 0.35 A

• 0.58 A

• 0.93 A

Answer 1

A 10 µF capacitor is connected to a 210 V, 50 Hz source as shown in figure. The peak current in the circuit is nearly 0.93 A.

Explanation:

Given: Capacitance (C) = 10 µF = 10 × 10⁻⁶ F

RMS Voltage (V_rms) = 210 V

Frequency (f) = 50 Hz

Constant (π) = 3.14

Peak voltage (V₀) = `V_"rms" * sqrt 2`

Capacitive Reactance (X_C) = `1/(2 pi f C)`

Peak current (I₀) = `V_0/X_C` = V₀(2πfC)

= `(210 xx sqrt 2) xx (2 xx 3.14 xx 50 xx 10 xx 10^-6)`

= 296.94 × 6.28 × 50 × 10⁻⁶

= 296.94 × 0.000314

= 0.0932 A

∴ The peak current in the circuit is nearly 0.93 A.