Advertisements
Advertisements
प्रश्न
9 is subtracted from the product of p and 4, the result is 11. The value of p is ______.
Advertisements
उत्तर
9 is subtracted from the product of p and 4, the result is 11. The value of p is 5.
Explanation:
Given, 9 is subtracted from the product of p and 4.
Then, 4p – 9 = 11
⇒ 4p = 11 + 9 ...[Transposing –9 to RHS]
⇒ 4p = 20
⇒ `(4p)/4 = 20/4` ...[Dividing both sides by 4]
∴ p = 5
Hence, the value of p is 5.
APPEARS IN
संबंधित प्रश्न
Solve the following equation and check your result:
5t − 3 = 3t − 5
Solve the following equation and check your result:
4z + 3 = 6 + 2z
In the equation 3x – 3 = 9, transposing –3 to RHS, we get 3x = 9.
If `x/3 + 1 = 7/15`, then `x/3 = 6/15`
Solve the following:
`8/x = 5/(x - 1)`
Solve the following:
`(5(1 - x) + 3(1 + x))/(1 - 2x) = 8`
Solve the following:
`(y - (4 - 3y))/(2y - (3 + 4y)) = 1/5`
Solve the following:
`(2x - 1)/5 = (3x + 1)/3`
Solve the following:
`(5x + 1)/(2x) = - 1/3`
Solve the following:
`m - (m - 1)/2 = 1 - (m - 2)/3`
