Question

8.2 grams of calcium nitrate is decomposed by heating according to the equation

\[\ce{2Ca(NO3)2 -> 2CaO + 4NO2 + O2}\]

Calculate the following:

Volume of nitrogen dioxide obtained at STP

[Atomic weights: Ca − 40, N − 14, 0 − 16]

Answer 1

328 g of calcium nitrate liberated

4 × 22.4 lit of NO₂

8.2 g of calcium nitrate liberated

`(4 × 22.4 × 8.2)/328`

= 2.24 lit of NO₂