Question

60 cm³ of oxygen was added to 24 cm³ of carbon monoxide and mixture ignited. Calculate the volume of oxygen used up.

Answer 1

\[\ce{2CO + O2 → 2CO2}\]
2 V         1 V        2 V

2 V CO requires oxygen = 1 V

so, 24 cm³ CO will require = 24/2 =12 cm³

Answer 2

\[\ce{2CO + O2 → 2CO2}\]

According to this equation,

Volume of oxygen used for 44800 cm³ of carbon monoxide = 22400 cm³

∴ Volume of oxygen used up for 24 cm³ of carbon monoxide = `22400/44800 xx 24` cm³

= 12 cm³